Question

1. a ) Derive the expression for electric field intensity at a point on the axial line of an electric dipole.
b) what can be the expression in the case of a point dipole.​

Answer 1

hlo mate here is ur ans......

A)  Consider the an electric dipole of charges +q and −q separated by distance 2a with center at O.

Goal: To find electric field at point P on the axial line of the dipole, OP=r.

Let E1​ and E2​ be electric field on P due to charges +q and −q respectively.

E1​ = kq/(r-a)^2 along AP

E2 ​=kq​/(r^2-a^2)^2  along BP

The resultant electric field at P, E=E1​−E2​ (as both E1​ and E2​ are in opposite direction)

E = kq/(r-a)^2-kq/(r+a)^2

==> kq*4ra/(r^2-a^2)^2

Define,  p=2aq

E = k(2pr/r^2-a^2)^2

If r>>a, then E = k*2pr/r^4 = k*2p/r^3

If r>>a, then E = k*2p/r^3......

B)A point (electric) dipole is the limit obtained by letting the separation tend to 0 while keeping the dipole moment fixed. The field of a point dipole has a particularly simple form, and the order-1 term in the multipole expansion is precisely the point dipole field.....

hope this hepls uh dear :)

pls mark as brainliest....