Question

1 A diagonal of the polugon pases outside of polygon such type of polygon is called_____________.

2 find the sum of interior Angels of octagen?

( slove on paper please)​

Answer 1

Answer:

We know that if a polygon has ‘n’ sides, then it is divided into (n – 2) triangles.  

We also know that, the sum of the angles of a triangle = 180°.

Therefore, the sum of the angles of (n – 2) triangles = 180 × (n – 2)

= 2 right angles × (n – 2)

= 2(n – 2) right angles

= (2n – 4) right angles

Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles.

Thus, each interior angle of the polygon = (2n – 4)/n right angles.

Answer 2

Answer:

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Step-by-step explanation:

We know that if a polygon has ‘n’ sides, then it is divided into (n – 2) triangles.  

We also know that, the sum of the angles of a triangle = 180°.

Therefore, the sum of the angles of (n – 2) triangles = 180 × (n – 2)

= 2 right angles × (n – 2)

= 2(n – 2) right angles

= (2n – 4) right angles

Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles.

Thus, each interior angle of the polygon = (2n – 4)/n right angles.