Question

1) A die is thrown. Find the probability of getting
i) an odd number.
ii) a perfect square.
iii) a number greater than 3​

Answer 1

Answer:

A die = 1,2,3,4,5,6

Step-by-step explanation:

A) . 1,3,5. n (A) =3

p of A = nA) /n of s

=3/6=1/2

B.=1,4 n of B =2

p of B = 1/3

C. =4,5,6

p of c = 3/6 =1/2

Hope u understand.

Answer 2

Answer:

(1) total no. of events= 6.

no. of favourable events= 3(1,3,5)

therefore P(E)= no.of favourable events÷ total no. of events

= 3÷6

=1÷2.

(2) total no. of events= 6.

no. of favourable events= 2 (1,4)

therefore P(E)= 2÷6

=1÷3.

(3) total no. of wvents= 6

no. of favourable events= 3(4,5,6)

therefore P(E)= 3÷6

=1÷2.

Step-by-step explanation:

hope this helps!!