1.A diverging lens has a focal length of 3cm. Calculate its power
2.The power of combination of two lenses X and Y is 50. the focal length
of lens X is15 cm.calculate the focal length of Y.
3.A concave lens has focal length 15am At wat distance should the
object from the lens to be placed so that it forms an image 10 cm from the
ans. Also find the magnification.
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Answer:
power=-0.33
Focal length of Y=13/30=0.43
Using mirror formula
f=-15 v=-10
u=-30
Magnification=1/3=0.33
Image will be Virtual erect and diminished
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