Physics, asked by aakash5228, 5 months ago

1. A drop of olive oil of radius 0.30 mm spreads into a
rectangular film of 30 cm x 15 cm on the water
surface. Estimate the molecular size of olive oil.​

Answers

Answered by Anonymous
8

Answer:

Given -

A drop of olive oil radius 0.30 my spreads into a rectangular film of 30 CM × 15 CM

To Find -

The molecular size of olive oil

Solution -

total \: volume =  \frac{4}{3} r( \frac{0.3}{10} )^{3}  {cm}^{2}

 =  \frac{4}{3} r \: (0.03)^{3}  {cm}^{2}

now \:  \frac{4}{3}r \: (0.03)^{3} = d \times 30 \times 15

 = d =  \frac{4r(0.03)^{3} }{3 \times 30 \times 15} cm

 = 2.51 \times  {10}^{ - 7} cm

Thank You

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Answered by Anonymous
11

Answer:

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Explanation:

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