Question

1. A farmer has enough food to feed 100 animals in his cattle for 20 days. How long
would the food last if there were 25 more animals in his cattle?​

Answer 1

Answer:

the ans is =

Step-by-step explanation:

no of animals added =25

total no of animals=100+25=125

for more no of animals the food will last for less days

in case of inverse variation

thus we have :125 x X=100 x 6

or                       X= (100 x 6)/125=4.8

so it is approx to 5 days

hope it helps

Answer 2

Answer:

16 days

Step-By-Step Explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Let the required number of days be p.

$\because x_1y_1 = x_2y_2$

Where,

$x_1 = 100, \: y_1 = 20, \: x_2 = 125$ and $y_2 = p$ (let)

=> 100 × 20 = 125 × p

=> 2000 = 125p

=> p = 2000/125

=> p = 16

Hence the required number of days = 16.