Question

1) A father is 25 years older than his son. After 8 years, the ratio of their ages will be 13:8. Find their present ages.
2) The difference of two numbers is 4. The larger number exceeds three times the smaller number by 2. Find the numbers​

Answer 1

Step-by-step explanation:

LET THE AGE OF FATHER BE X

LET THE AGE OF SON BE Y

ACCORDING TO THE QUESTION ,

Y=X+25---------------------------eq¹

After 8 years.....

Age of father will be x+8

Age of son will be x+25+8 = x+33

The ratio of their ages is,

x+8/x+33 = 13/8

8(x+8) = 13(x+33)

8x+64 = 13x + 429

13x-8x = 429-64

5x = 365

x = 365/5 = 73

Now put x = 73 in eq¹

y = x+25

y = 73 + 25

y = 98

THEREFORE , AGE OF FATHER IS 98 AND AGE OF SON IS 73

Answer 2

Answer:

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