Question

1) A father is 3 times as old as
his son. After 15 years, he will
be twice as old as his son, what
are there present ages?​

Answer 1

Step-by-step explanation:

Let Son age be x

Father age is 3x

After 15 years ,

Son age be y

father age is 2y

present ages is

Answer 2

Answer:

let the present age be X

age of a father = 3X

a/p,

3X+15= 2(X+15)

3X = 2X+30

3X-2X=30

X=30

hence the age of son= 30 years

the age of father = 90 years.