1- A father is 7 time as old as his son. Two years ago, the father was 13 times as old as his son. How
old are they now?
Answers
Answered by
1
Step-by-step explanation:
2 years ago the father was 13 times as old as his son, how old are they now. DAD=7X WHEN THE SON'S AGE IS X NOW. X=4 THE AGE OF THE SON NOW. THUS THE DAD=7*4=28 YEARS OLD NOW.
hope it helps
Answered by
1
Answer:
Let the age of the son be x.
Therefore,
Age of father = 7 times son's age = 7x
Two years ago,
son's age = x-2 and father's age=7x-2
According to question,
7x-2 = 13(x-2)
=> 7x-2 = 13x - 26
=> 13x-7x = -2+26
=> 6x=24
=> x = 4 years(Son's age)
father age = 7x = 28 years.
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