Question

1- A father is 7 time as old as his son. Two years ago, the father was 13 times as old as his son. How
old are they now?​​

Answer 1

Answer:

⟹13(x−2)=7x−2

:⟹13x−26=7x−2

:⟹13x−7x=26−2

:⟹6x=24

:⟹x=

6

24

:⟹

x = 4

★

Answer 2

Step-by-step explanation:

2 years ago the father was 13 times as old as his son, how old are they now. DAD=7X WHEN THE SON'S AGE IS X NOW. X=4 THE AGE OF THE SON NOW. THUS THE DAD=7*4=28 YEARS OLD NOW.