Question

1. A father is twice as old as his son. 20 years ago, the age
of the father was 12 times the age of the son. The present
age of the son is​

Answer 1

Let son be x years

father = 2x

..

20 years ago

son = x-20

father = 2x-20

..

2x-20=12*(x-20)

2x-20 = 12x -240

add 20 to both sides

2x = 12x-240+20

2x=12x-220

add -12x to both sides

2x-12x= 12x-12x-220

-12x+2x= -240+20

-10x= -220

divide by -10

x= -220/-10

x=22 son's age

Father's age = 2*22 = 44 years