1). a feild in the form of parallelogram has baseb32 m altitude 1.75 m . find the cost of watering the field at rupees 8": per sq.m
2) a parallelogram has side ofv20 cm and 15 cm and the perpendicular distance between the sides is 18 cm .. find the distance between 15 cm side
3). the base of a parallelogram is twice its height. if the area of parallelogram is 392 sq. cm , find the base and the height
plzzzzz I will mark as brainlisttt
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answer of first question is
first we have to find the area of parallelogram.
formula to calculate the area of parallelogram is base *height
it is 32*1.75
=560 sq. cm.
then we've to find the cost of watering
=560*8
=4480 rs
and here you are
the cost of watering the field is 4480 rs.
now the answer of your second question I think you've missed something in the question. something has not been mentioned.
do as you said..
helped mark as brainliest
first we have to find the area of parallelogram.
formula to calculate the area of parallelogram is base *height
it is 32*1.75
=560 sq. cm.
then we've to find the cost of watering
=560*8
=4480 rs
and here you are
the cost of watering the field is 4480 rs.
now the answer of your second question I think you've missed something in the question. something has not been mentioned.
do as you said..
helped mark as brainliest
shammu2:
but therer is not written so howww
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