Question

1. a) Find a real root of x3 – x – 1 = 0 between 1 and 2 by

bisection method.

x3 – x – 1 = 0 H$m EH$ dmñV{dH$ ‘yb Omo {H 1 Ed§ 2 Ho$ ‘ܶ

pñWV h¡ ~m¶go³eZ {d{Y Ûmam kmV H$s{O¶o&

b) Find by Newton Raphson’s method, the real root of the

equation 3 cos 1 x x = + .

g‘rH$aU 3 cos 1 x x = + H$m dmñV{dH$ ‘yb ݶyQ>Z aoâgZ {d{Y

Ûmam kmV H$s{O¶o&​

Answer 1

Answer:

x3 +3x2 =6x2equation is 3+1=4