За – 1/a :(find the cube )
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(3a - 1/a)^3
using, (x - y)^3 = (x)^3 - (y)^3 - 3(x)(y)(x-y)
= (3a)^3 - (1/a)^3 - 3(3a)(1/a)(3a - 1/a)
= 27^a3 - 1/a^3 - 9(3a - 1/a)
= 27^a3 - 1/a^3 - 9(3a^2 - 1/)
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