Question

1 A flooring tile has the shape of a parallelogram whose base is 24 cm and the
corresponding height is 10 cm. How many such tiles are required to cover a floor of
area 1080 mº?

Answer 1

Answer:

Area of the flooring tile = base x height

= 24 x 10 = 240 sq.cm

Area of the floor = 1080 sq.m = 10,800,000 sq.cm

No.of tiles required = 10,800,000/240 = 45000

Therefore, the required number of tiles is 45000.

Answer 2

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

$\huge\purple{24 \times 10}$

$\huge\purple{240 {cm}^{2} }$

$\huge\purple{0.024 {m}^{2} }$

$\red{no. \: of \: tiles \: = \frac{area \: of \: room}{area \: of \: one \: tile} }$

$\huge\orange{ \frac{1080}{0.024} }$

$\pink{so... \: 45000 \:tiles \: are \: needed }$