Question

1. A football is kicked with an initial
velocity of 25 m/s at an angle of
45-degrees with the horizontal,
Determine the time of flight, the
horizontal distance, and the peak
height of the football.

Please anyone explain the answer step by step .
It is my assignment within today evening I want to submite this assignment so .kindly answer this question with step by step please​

Answer 1

Answer:

The equation of a projectile motion is a parabola, which is given by:

y=x tan 0 - (g /2u2cos20) x2

where, x=horizontal distance travelled by object in time to

y = vertical distance travelled in time

t

0= angle of projection

u=velocity of projection

Given : u = 25/s,x=7m

Hence, y = 7 tan 0-72g/2x252cos20

y =7tan 0-49g/1350cos20