Question

1. a force of 100 newton is applied on an object having dimnesion 2×4×6cm. find pressure
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|force and pressure |
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Answer 1

Question

A force of 100 newton is applied on an object having dimnesion 2×4×6cm. Find pressure.

Solution

Given,

Force applied on the object,F = 100 N

Dimensions of the cuboidal object = 2 × 4 × 6 cm

Firstly,we need to find the total surface area of the cuboidal object

$\boxed{\boxed{\sf TSA \ of \ Cuboid = 2(lb + bh + lh)}}$

Substituting the values,we write :

» TSA of Cuboid = 2[(2)(4) + (4)(6) + (6)(2)]

» TSA of Cuboid = 2(8 + 24 + 12)

» TSA of Cuboid = 2 × 44

» TSA of Cuboid = 88 cm²

Physical Quantity should be in its corresponding SI units

» TSA of Cuboid = $88 × 10^{- 4}$ m²

Now,

Pressure is given as :

$\sf Pressure = \dfrac{Force}{Area}$

$\longrightarrow \sf P = \dfrac{100}{88 \times 10^{-4}} \\ \\ \longrightarrow \sf P = \dfrac{10^{6}}{88} \\ \\ \longrightarrow \sf \boxed{\boxed{\sf P = 113636.63 \ Pascals}}$

Answer 2

Answer:

Refer the attached picture.

Pressure = 1.14 × 10^4 Pa