(1) A force of 1200 N acts on the surface of area 10 cm² normally. What would be the pressure on the surface?
(2) The elephant weighs 20,000 N stands on one foot of area 1000 cm². How much pressure would it exert on the ground?
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Given:
1) Force = 1200 N
Area = 10 cm²
2) Force = 20,000 N
Area = 1000 cm²
To find:
Pressure = ?
Solution:
1) 1 cm² = 10^-4 m²
10 cm² = 10^-3 m²
Pressure = Force/ Area
Pressure = 1200/ 10^-3
Pressure = 1200 × 10³
Thus, Pressure = 1200000 N/m²
2) 1 cm² = 10^-4 m²
1000 cm² = 10^-1 m²
Pressure = Force / Area
Pressure = 20000/10^-1
Pressure = 20000 × 10¹
Thus, Pressure = 200000 N/ m²
Required Answer:
Therefore,
- The pressure on the surface is 12,00,000 N/m²
- The pressure exerted by elephant on ground is 2,00,000 N/m²
Basic Points:
# Unit of pressure is Newton per square meter(N/m²) or Pascal(Pa)
# 1 Pa = 1 N/ m²= 1 × 10 ^ -5 bar
# Solve more such question to get a good hold on it
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