Question

1. A grain was found to contain 11.5% moisture. A 5.2146- g sample was placed into a crucible (28.5053 g tare). The ashed crucible weighed 28.5939 g. Calculate the percentage ash on (a) an as-received (wet weight) basis and (b) a dry matter basis.

2. You wish to have at least 100 mg of ash from a cereal grain. Assuming 2.5% ash on average, how many grams of the grain should be weighed for ashing​

Answer 1

Answer:

I don't know sorry byeéeee

Answer 2

1)(A) 1.70% (B)1.92%

2) 4g sample

1) Given:

A grain was found to contain 11.5% moisture.

5.2146g sample was placed into a crucible(28.5053g tare).

The ashed crucible weighed 28.5939g.

To find:

Calculate the percentage ash on

(a) an as-received basis (wet weight)

(b) a dry matter basis

Solution:

Crucible + ash = 28.5939 g

Tared crucible = 28.5053 g

Ash = ( Crucible + ash) - ( Tared crucible)

⇒ 0.0886g

(a) The percentage ash as on wet weight

=  $\frac{0.0886g of Ash}{5.2146g of sample} * 100$

= 1.70%

(b) Dry matter basis

⇒ 5.214g of sample * $\frac{11.5g of water}{100g sample}$ = 0.5997g water

⇒ 5.214g sample - 0.5997g water = 4.6149g sample dry weight

≅ $\frac{0.0886g Ash}{4.6149g dry wt sample} * 100%$

≅ 1.92%

Hence, (a) wet weight = 1.70% and (b) dry weight = 1.92%

2) Given:

A cereal grain to have at least 100mg of ash

To find:

Assuming 2.5% ash on average, how many grams of grain should be weighed for ashing

Solution:

100mg = 0.1g of ash

2.5% = 2.5g of ash/ 100g of sample

= $\frac{2.5g ash}{100g sample} = \frac{0.1g ash}{x}$

⇒ 2.5$x$ = 10

≅ x= 4g sample.

Hence, 4g of the grain should be weighed for ashing.

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