Question

1) A grandfather is ten times older than his granddaughter. He is also 54 years older than

her. Find their present ages.

2.) Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older

than Baichung. The sum of the ages of all the three is 135 years. What is the age of

each one of them?

3.) Fifteen years from now Ravi’s age will be four times his present age. What is Ravi’s

present age?

4) Aman’s age is three times his son’s age. Ten years ago he was five times his son’s

age. Find their present ages.




Who will give the correct answer first....... To him/her I will mark as brainliest ​

Answer 1

Pls mark as brainliest answer

Answer 2

Answer:

Hello friend, here's ur answer.

Step-by-step explanation:

1) Grandfather's age: - 10x

  Granddaughter's age: - x

10x=x+54

10x-x=54

9x=54

x=54/9

x=6

Grandfather's age = 10x = 10*6 = 60 Years

Granddaughter's age = x = 6 Years

2) Baichung's father's age = x

Baichung's grandfather's age = x+26

Baichung's age = x-29

(x)+(x+26)+(x-29) = 135

3x-3=135

3x=135+3=138

3x=138

x=138/3

x= 46 Years

Baichung's Age: - 46-29 = 17 Years

Baichung's father's age: - 46 Years

Baichung's grandfather's age: - 46+26 = 72 Years

3) Ravi's present age: - x

x+15 = 4x

15=4x-x

15=3x

x=15/3

x= 5 years

4) Son's age= x

Aman's age=3x

5(x-10) = 3x-10

5x-50=3x-10

2x=40

x=20

Son's age=20 Years

Aman's age=60 Years