1. A grindstone starts from rest and has a constant
angular acceleration of 3.0 rad/s. Find : (i) the
angular displacement, (ii) the angular speed, after 2.0
second.
Answers
Answered by
3
Explanation:
ii) angular speed w= angular acceleration a ×timet
w= a×t =3×2=6 rad/s
i) angular displacement = d
w^2 = 2×a×d
d is=36/2×3=6rad
Answered by
0
Answer:
w=at
=3x2= 6rad/s.
w2 = 2ad
d = 36/(2*3) = 6 rad.
Similar questions