1)A hammer exerts a force of 1.5 N on each of the two nails A and B. The area of the cross section of the tip A is 2 mm^2 while that of nail B is 6 mm^2. Calculate the pressure on each nail.
(Best answer with well explanation will be chosen as brainlist.)
Answers
Solution :
In this Question , We have Provided with a hammer exerts a force of 1.5 N on each of the two nails A and B. The area of the cross section of the tip A is 2 mm^2 while that of nail B is 6 mm^2 and We need to Calculate the Pressure on each nail . Let us Solve it one by one :
Finding the Approach :
In order to find the Pressure on First Nail and Second Nail We need to understand the approach of the above question .
Given :
Force = 1.5 Newton
⇒ 1mm = 0.001m
(Implies , the Sqaure of 1mm is equal to 0.000001 m^2 Which is Equal to 10^-6 m^2)
Finding the Pressure Exerted by First Nail or A
Area of Cross Section 2mm^2
⇒ (1.5)/(2 *10^-6)
⇒ 7.5 * 10^5 Pascal
Finding the Pressure Exerted by Second Nail or B
Area of Cross Section 6mm^2
⇒ (1.5)/(6*10^-6)
⇒ 2.5 * 10^5 Pascal
Therefore , the Pressure exerted on first nail is 7.5 * 10^5 Pascal and the Pressure Exerted on Second Nail is 2.5 * 10^5 Pascal .
» CASE 1)
For Nail A :-
• Force (F) = 1.5 N
• Area of cross-section (A) = 2 mm²
=> 2 × m²
_______________ [ GIVEN ]
• We have to find Pressure (P) for nail A.
______________________________
We know that ..
→ Pressure =
=>
=>
=> N/m² or Pa
______________________________
N/m² or Pa is the pressure on nail A.
___________ [ ANSWER ]
______________________________
» CASE 2)
For Nail B :-
• Force (F) = 1.5 N
• Area of cross-section (A) = 6 mm²
=> 6 × m²
_______________ [ GIVEN ]
• • We have to find Pressure (P) for nail B.
______________________________
Now..
→ Pressure =
=>
=>
=> N/m² or Pa
______________________________
N/m² or Pa is the pressure on nail B.
___________ [ ANSWER ]
______________________________