Physics, asked by Anonymous, 9 months ago

1)A hammer exerts a force of 1.5 N on each of the two nails A and B. The area of the cross section of the tip A is 2 mm^2 while that of nail B is 6 mm^2. Calculate the pressure on each nail.

(Best answer with well explanation will be chosen as brainlist.)

Answers

Answered by FuturePoet
67

Solution :

In this Question , We have Provided with a hammer exerts a force of 1.5 N on each of the two nails A and B. The area of the cross section of the tip A is 2 mm^2 while that of nail B is 6 mm^2 and We need to Calculate the Pressure on each nail . Let us Solve it one by one :

Finding the Approach :

In order to find the Pressure on First Nail and Second Nail  We need to understand the approach of the above question .

Given :

Force = 1.5 Newton

⇒ 1mm = 0.001m

(Implies , the Sqaure of 1mm is equal to 0.000001 m^2 Which is Equal to 10^-6 m^2)

Finding the Pressure Exerted by First Nail or A

Area of Cross Section 2mm^2

⇒ (1.5)/(2 *10^-6)

⇒ 7.5 * 10^5 Pascal

Finding the Pressure Exerted by Second Nail or B

Area of Cross Section 6mm^2

⇒ (1.5)/(6*10^-6)

⇒ 2.5 * 10^5 Pascal

Therefore , the Pressure exerted on first nail is 7.5 * 10^5 Pascal and the Pressure Exerted on Second Nail is 2.5 * 10^5 Pascal .

Answered by Anonymous
75

» CASE 1)

For Nail A :-

• Force (F) = 1.5 N

• Area of cross-section (A) = 2 mm²

=> 2 × {10}^{-6}

_______________ [ GIVEN ]

• We have to find Pressure (P) for nail A.

______________________________

We know that ..

→ Pressure = \dfrac{Force}{Area}

=> \dfrac{1.5}{2 \:  \times  \:  {10}^{ - 6} }

=> \dfrac{1.5\:\times\:{10}^{6}}{2}

=> 7.5\:\times{10}^{5} N/m² or Pa

______________________________

7.5\:\times{10}^{5} N/m² or Pa is the pressure on nail A.

___________ [ ANSWER ]

______________________________

» CASE 2)

For Nail B :-

• Force (F) = 1.5 N

• Area of cross-section (A) = 6 mm²

=> 6 × {10}^{-6}

_______________ [ GIVEN ]

• • We have to find Pressure (P) for nail B.

______________________________

Now..

→ Pressure = \dfrac{Force}{Area}

=> \dfrac{1.5}{6 \:  \times  \:  {10}^{ - 6} }

=> \dfrac{1.5\:\times\:{10}^{6}}{6}

=> 2.5\:\times{10}^{5} N/m² or Pa

______________________________

2.5\:\times{10}^{5} N/m² or Pa is the pressure on nail B.

___________ [ ANSWER ]

______________________________

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