Question

1. A hollow sphere has a radius of 10 cm and bears a charge
of 5 nC. If the sphere is isolated, the potential at a distance
50 cm from the centre of the sphere is
hi AV (c) 90 V (d) 120 y​

Answer 1

The potential at a distance  50 cm from the center of the sphere is 90 volts.

Given:

Charge = q  = 5 nC = 5 × 10⁻⁹ C

Radius = 10 cm

Distance = r  = 50 cm = 50 × 10⁻² m

Explanation:

The potential at a distance is given by the formula:

V = 1/(4πε) × q/r

On substituting the values, we get,

V = 9 × 10⁹ × (5 × 10⁻⁹)/(50 × 10⁻²)

V = 45/(1/2)

∴ V = 90 V