Question

1) A large ball 2 m in radius is made up of a
rope of square cross section with edge
length 4 mm. Neglecting the air gaps in
the ball, what is the total length of the
rope to the nearest order of magnitude?​

Answer 1

Volume of the rope = Volume of the sphere

length of the rope × cross area of the rope = Volume of the sphere

Let the length of the rope be x

x × $4^{2}$ = 4/3 × π × 2³

x =  4/3×$4^{2}$ × π × 2³

x = 4 × 22 × 8 / 16 ×7

x = 2.096 ×$10^{6}$

Order of magnitude = $10^{6}$ m = 10³ km

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