Math, asked by aarti19j, 3 months ago

1. A leather shop makes custom-designed, hand-tooled briefcase and luggage. The shop makes a profit of Rs. 400 from each briefcase and a Rs. 200 profit from each piece of luggage. The shop has a contract to provide a store with exactly 30 items per months. A tannery supplies the shop with at least 80 square yards of leather per month. The shop must use at least this amount but can order more. Each briefcase requires 2 square yard of leather while each piece of luggage requires 8 square yards of leather. From the past performance, the shop owner know that they cannot make more than 20 briefcase per month. Formulate the LP problem and solve it graphically​

Answers

Answered by Anonymous
3

So far we have discussed maximization problems with all constraints and minimization problems with all constraints. However, we have yet to solve a problem with a mixture of , , and = constraints. Furthermore, we have not yet looked at a maximization problem with a constraint. The following is a maximization problem with , , and = constraints.

A mixed constraint problem includes a combination of , =, and constraints.

A leather shop makes custom-designed , hand-tooled briefcases and luggage. The shop makes a $400 profit from each briefcase and a $200 profit from each piece of luggage. (The profit for briefcases is higher because briefcases require more hand tooling.) The shop has a contract to provide a store with exactly 30 items per month. A tannery supplies the shop with at least 80 square yards of leather per month. The shop must use at least this amount but can order more. Each briefcase requires 2 square yards of leather; each piece of luggage requires 8 square yards of leather. From past performance, the shop owners know they cannot make more than 20 briefcases per month. They want to know the number of briefcases and pieces of luggage to produce in order to maximize profit.

This problem is formulated as

where x 1 = briefcases and x 2 = pieces of luggage.

Similar questions