Question

1. A lever raised 500 N load using 200 N effort. If load distance and effort distance are 20 cm and 60 cm respectively, calculate mechanical advantage, velocity ratio and efficiency of this lever. [MA = 2.5, VR =3 and = 83.33%]​

Answer 1

Answer:

A lever raised 500 N load using 200 N effort. If load distance and effort distance are 20 cm and 60 cm respectively.

• Mechanical advantage = 2.5

• Velocity ratio = 3

• Efficiency = 83.33%

Explanation:

Given,

Load (L)  =  500 N                 Effort (E)  =  200N  

Load distance ($L_{d}$ ) = 20 cm   =  0.2 m

Effort distance ($E_{d}$ ) = 60 cm  =  0.6 m

The mechanical advantage is given by,

•  $Mechanical\ advantage (M.A) = \frac{Load}{Effort}$

          $M.A = \frac{500}{200} = 2.5$

The velocity ratio is given by,

• $Velocity\ ratio\ (V.R) = \frac{E_{d} }{L_{d} }$

          $V.R = \frac{60}{20} = 3$

The efficiency is given by

• $\text { Efficiency, } \eta=\frac{M A}{V R} \times 100 \%$

           $\eta=\frac{2.5}{3} \times 100 \%$

              = 83.33 %