Question

1. A line AB is of length 6 cm. Another line CD is of length 15 cm. What fraction is
(i) the length of AB to that of CD ?
(ii) 1/2 the length of AB to that of 1/3 CD ?
(iii) 1/5 of CD to that AB​

Answer 1

Step-by-step explanation:

Given = AB = 6 cm, CD = 15 cm.

$(i) \frac{AB}{CD} = \frac{6}{15}$

$(ii) \frac{ \frac{1}{2} \times AB} { \frac{1}{3} \times CD} = \frac{ \frac{1}{2} \times 6 }{ \frac{1}{3} \times 15} = \frac{3}{5}$

$(iii) \frac{ \frac{1}{5} \times CD}{AB} = \frac{ \frac{1}{5} \times 15}{6} = \frac{3}{6} = \frac{1}{2}$

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