Question

1. A liquid is kept in cylindrical vessel which is rotating along its axis. The liquid rises at the sides. If the radius of the vessel is 0.05 m and the speed of rotation is 2 rev. per second, find the  difference in the height of the liquid at the centre of the vessel and its side (g = 9.8 m/s2)

Answer 1

according to the bernoulli's theorem:p+12ρv2 = constantwe knoe v = rωapplying these equation at the side wall and centre of the vesselpcentre 12ρvcentre2 = pside 12ρvside2 vcenter = 0pcentre −pside = 12ρr2ω2hρg =12ρr2ω2h = 12gr2ω2 = 1×0.05×0.05×(2π×2)220 = 0.02 m= 2 cm

Hope u understand

Answer 2

according to the bernoulli's theorem:p+12ρv2 = constantwe knoe v = rωapplying these equation at the side wall and centre of the vesselpcentre 12ρvcentre2 = pside 12ρvside2 vcenter = 0pcentre −pside = 12ρr2ω2hρg =12ρr2ω2h = 12gr2ω2 = 1×0.05×0.05×(2π×2)220 = 0.02 m= 2 cm