Question

1. A man exerts a pressure of 14 Pa by applying a force of 42 N on a box. Calculate the area over which the force is applied.

2. Calculate the force applied on an area of 136 cm² to exert a pressure of 17 Pa.

note : answer any one of the question


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Answer 1

1. P = F/A

14Pa = 42/A

A = 42/14

A = 3 m²

2. P = F/A

17Pa= F/136 cm²

F = 17 × 136

F = 2312 N

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Answer 2

Answer:

1. Area over which the force applied is equal to 3m².

2. Force applied on area 136cm² is equal to 0.2312N.

Explanation:

1.  Given: man exerts pressure, $P=14Pa$

Force applied on the box , $F=42N$

The pressure is  force acting on per unit area of surface.

Pressure= (Force)/(area)

Area over which the force applied=Force/pressure

Area, $A=\frac{F}{P}$

$A=\frac{42N}{14Pa}$

$A=\frac{42N}{14Nm^{-2} }$

$A=3m^{2}$

Therefore, the area upon which force applied is equal to 3m².

2.  Given: pressure exerted, $P=17Pa$

Area over which the force applied, $A=136m^{2}$

Pressure= (Force)/(area)

⇒ Force = Pressure × Area

⇒ Force, $F=(17Pa)(136*10^{-4}m^{2})$

⇒  $F=2312*10^{-4}Pa.m^{2}$

⇒  $F=0.2312(Nm^{-2})(m^{2})$

∴   $F=0.2312N$

Therefore, applied force is equal to 0.2312N.