Question

1. A man exerts a pressure of 14 Pa by applying a force of
42 N on a box. Calculate the area over which the force is
applied
2. A pendulum oscillates 40 times in 4 seconds. Find its
time period and frequency.​

Answer 1

Answer:

(1) 3 m² (2) time period= 0.1 seconds, frequency= 10

Explanation:

1. pressure= thrust/area

area= thrust/pressure

= 42/14 m²

= 3m²

2. time period= time/oscillations

= 4/40 s

= 0.1 s

frequency= oscillations/time

=40/4

= 10

Answer 2

1] area over which the force is applied is=

pa= n/m^2

14= 42/m^2

area wil be 3m^2

2] Time = 4 sec. Time Period = (4/40) = 0.1 sec. Frequency = (Number of Oscillations)/ (Time taken)Frequency = (40/4) =10Hz.

good day!