Question

1. A man gave 25% of the amount of money with him to his eldest son, 20% to his
younger son and 20% of the remainder to his daughter and the rest 880 to his wife
Find the amount of money he had with him and also find the ratio of the money
received by his eldest son to his younger son and to his daughter.
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Answer 1

Answer:

Amount of Money he had 2000

ratio 25:20:11

Step-by-step explanation:

let he had 1000 amount of money

elder son gets 25% i.e 250

younger gets 20% i.e 200

remaining = 1000-(250+200)

                 = 550

daughter gets 20% of 550 i.e 110

wife gets remaining i.e = 1000-(250+200+110)=440

But in question it is given 880 which is 440x2

Therefore everything should be x2

amount 2000

elder son 500

younger 400

daughter 220

Answer 2

Answer:Rs.2000 ratio=25:20:11

Step-by-step explanation:

let the man have 100%

elder son=100%-25%=75%

remaining =75%

younger son= 75%-20%

remaining =55%

daughter= 20/100 X 55= 11%

remaining=55%-11%

=44%

44%=Rs.880

100%=?

Man has =Rs. 880 X 100/44

=Rs.2000

ratio = 25:20:11

hope it is helpful to u