Question

1. A man is 4 times as old as his son. After 16 years he will be only twice as old as his son. Find their
present ages​

Answer 1

Answer:

At present :

At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

Age of son = x years  

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given,

Therefore,

At present :

Son age = x = 8 years

Father age = 4x=4×8 = 32 years

•

Step-by-step explanation:

Answer 2

$\mathfrak{\huge{\green{\underline{Question:-}}}}$

A man is 4 times as old as his son. After 16 years he will be only twice as old as his son. Find their  present ages​.

$\mathfrak{\huge{\green{\underline{To \: Find:-}}}}$

The present age of the son.

The present age of the man.

$\mathfrak{\huge{\green{\underline{Solution:-}}}}$

Let the present age of father be x and the son be y.

Now,

$\sf x=4y$

After 16 years,

Age of father will be $\sf x+16$

Age of son will be $\sf y+16$

Therefore,

$\sf x + 16 = 2( y + 16)$

$\sf x + 16 = 2y + 32$

$\sf x = 2y + 16$

Finding the value of y,

$\sf 2y = 16$

$\sf y=\dfrac{16}{2}$

$\sf y=8$

Getting back to the value of x,

$\sf x=4 \times 8$

$\sf x=32$

Hence, the present age of father is 32 years and present age of son is 8 years.