1. A man is 6 times as old as his son. Three years ago, his age was 9 times his son's age at time. Find the present age of man.
Answers
Answer
Let the age of man be x
and the age of his son be y
According to the question:
After 6 years :
(x+6)=3(y+6)
⇒x−3y=12⟶(i)
Three years ago :
x−3=9(y−3)
⇒x−3=9y−27
⇒x−9y=−24⟶(ii)
Solving (i) and (ii),
6y=36
⇒y=6
Putting value of y in equation (i),
x−3xy=12
∴x=12+18
x=30
∴ Age of man =30 years.
Age of son =6 years.
Given: A man's age is 6 times as his son
three years ago his age was 9 times the age of his son at that time
To find: Present age of father and son
Step-by-step explanation:
Let the present age of son be x years.
Then, the present age of his father is 6x years.
Age of the son 3 years ago = (x-3) years
Age of father three years ago = (6x-3)
∴ According to question,
6x-3 = 9(x-3)
⇒ 6x-3 = 9x-27
⇒ 6x-9x = -27+3
⇒ -3x = -24
⇒ x = 8
∴ Son's present age = 8 years
Father's present age = 6x = 6×8
= 48years
Answer: Present ages of son and father is 8 years and 48 years respectively.