Question

1)
A man is thrice as old as his son. After 12 years, he will be twice as old as his son at that time. Find their present ages.



2)
A sum of 500 is in the form of notes of denominations of 5 and 10. If the total nhor of notes is 99. find the number of notes of each type.​

Answer 1

Answer:

1) answer - After 12 years, he will be twice as old as his son at that time. Find their present ages. ∴ Present age of son is 12 years and Present age of father is = 3x = 3 x 12 = 36 years

2)

Solution

Let the number of 5 rupee notes be x,then

The number of 10 rupee notes =90−x

Then ,according to the question

5x+10(90−x)=500

5x+900−10x=500

5x=400

x=80

There are 80 notes of Rs.5 and 10 notes of Rs.10.

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Answer 2

Answer:

1.) 36 yrs

2.) 10 Rs.

Step-by-step explanation:

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