Question

1. A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son
Find their present ages.

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$\huge{\overline{\underline{\bf{ANSWER}}}}$

son's age =22y.

man's age =44y.

Step by step,

Let the age of son be x

A/c

man's age=2x[present age]

and

before 20 years, i.e

2x-20 = 12(x-20)

2x-20=12x-240

220=10x

x=22

so,

man's age=44 y.

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