1. A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son
Find their present ages.
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son's age =22y.
man's age =44y.
Step by step,
Let the age of son be x
A/c
man's age=2x[present age]
and
before 20 years, i.e
2x-20 = 12(x-20)
2x-20=12x-240
220=10x
x=22
so,
man's age=44 y.
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