Math, asked by abu73, 10 months ago

1. A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son
Find their present ages.

Answers

Answered by kraokorrapati
0

Answer:

Step-by-step explanation:

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Answered by bhagirath0
1

\huge{\overline{\underline{\bf{ANSWER}}}}

son's age =22y.

man's age =44y.

Step by step,

Let the age of son be x

A/c

man's age=2x[present age]

and

before 20 years, i.e

2x-20 = 12(x-20)

2x-20=12x-240

220=10x

x=22

so,

man's age=44 y.

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