Question

1. A man is twice as old as his son. Twenty years ago, the father was 4 times as old as the son Find the present age of each.​

Answer 1

Answer:

Let the present age of son be x and of his father be 2x.

Before 20 year,

2x-20 = 4(x-20)

2x-20=4x-80

2x-4x=-80+20

-2x = -60

x=30.

So, age of son =30year

and age of father=60year

Answer 2

Answer:

Let the present age of son be x and of his father be 2x.

Before 20 year,

2x - 20 = 4(x - 20)

2x - 20 = 4x - 80

2x-4x=-80+20

- 2x = - 60

x = 30

So, age of son =30year and age of father = 60year.