Question

• 1 ) A man lifts a parcel weighing 5 newtons from the ground on to a
shelf 2 meters high. How much work does he do on the parcel?​

Answer 1

We know,

$\boxed{ W = F \ • \ s}$

We're given that, F or w = 5 N and displacement = 2 m.

∴ W = (5 N)(2 m)

⇒ W = 10 Nm

⇒ W = 10 J (answer).

More to know:-

Work done is a scalar quantity. It depends on,

• Force exerted on an object,
• displacement observed in the object,
• direction between the force and displacement occurred.

Answer 2

$\sf{Answer}$

Step-by-step-explanation

Given :-

• F = 5N
• s = 2m

To find :-

Work done

Formula :-

Work done is dot product of force & Displacement

W = F.S

Solution:-

Substuite value of given data in formula

W = F.S

W = 5 . 2

W = 10J

Explore more :-

Work can be measured in Joules

Work can be Kinetic energy or potential energy

W = mgh

W = 1/2 mv²

• Work done can be positive ,negative, zero