1.A man pulls a box to a distance of 5 m along a horizontal floor through a cord attached to the box which makes an angle of 39° with the horizontal. How much work is done if the force exerted on the cord is 60N?(with solution)
2.How much work is done in lifting a 19.6N box from the floor to the top of a table 0.8m high?(with solution)
3.What power will be required to raise a 14,700N steel beam to a height of 14 meters in 10 minutes?(with solution)
Answers
Answered by
1
Answer:
1. 11700 joule
2. 15.68
3. 343
Answered by
1
Explanation:
Given 1. A man pulls a box to a distance of 5 m along a horizontal floor through a cord attached to the box which makes an angle of 39° with the horizontal. How much work is done if the force exerted on the cord is 60 N?(with solution)
2. How much work is done in lifting a 19.6 N box from the floor to the top of a table 0.8 m high?(with solution)
3. What power will be required to raise a 14,700 N steel beam to a height of 14 meters in 10 minutes?(with solution)
- 1. So
- F = 60 N
- s = 5 m
- theta = 39 degree
- Work done is
- W = F s cos theta
- = 60 x 5 x cos 39
- = 300 x 0.77714
- W = 233.143 J
- 2. So we need to find the work done by an object.
- F = 19.6 N
- s = o.8 m
- W = F x s
- = 19.6 x 0.8
- W = 15.68 N-m
- W = 15.68 J
- 3. So we need too find the power.
- Now work done will be
- F = 14,700 N
- s = 14 m
- W = F x s
- = 14,700 x 14
- = 205800 N-m
- W = 205800 J
- So t = 10 min
- 1 min is 60 secs
- 10 min = 60 x 10
- = 600 secs
- Power P = W / t
- = 205800 J / 600 s
- P = 343 W
Reference link will be
https://brainly.ph/question/18581272
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