Math, asked by rosemarymema221, 1 month ago

(1) A man's property of Rs. 2 00 000 was divided between his wife and son such that his wife got thrice as his son. Find his wife's share. (ii) Divide 300 into two parts such that one is two thirds of the other.​

Answers

Answered by vijay14321u
6

Step-by-step explanation:

total property of man= 2,00,000

ratio of wife and son = 3:1 =

total value = 3+1 = 4

means 4 = 2,00,000

1 means = 50,000 (share of son)

3 means = 1,50,000 (share of wife).

ii) now total value = 300

let x= 2/3

then another is "y" = 1/3

x = 300 × 2/3 = 200

y = 300 × 1/3 = 100

Answered by tennetiraj86
26

Step-by-step explanation:

Solution :-

(1) Given that

The property of a man = Rs. 2,00,000

Let the share of his son be Rs. X

The share of his wife

= thrice the property of his son

= Rs. 3X

Sum of their shares = X + 3X = Rs. 4X

Therefore, 4X = 200000

=> X = 200000/4

=> X = 50000

Therefore, X = 50,000

The share of his wife = 3X = 3(50000)

= Rs. 150000

The share of his wife = Rs. 1,50,000

(2) Given that

The amount = Rs. 300

Let the other part be Rs. X

The one of the parts

= 2/3 of the other part

= (2/3) of X

= (2/3)×X

= Rs. 2X/3

Sum of the two parts = Rs. 300

=> X+(2X/3) = 300

=> (3X+2X)/3 = 300

=> 5X/3 = 300

=> 5X = 300×3

=> 5X = 900

=> X = 900/5

=> X = 180

Therefore, X = Rs. 180

If X = Rs. 180 then 2X/3 = 2(180)/3

= 360/3 = Rs. 120

The two parts are Rs. 180 and Rs. 120

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