Question

1. A man walks at a speed of 1 m/s and covers a certain distance in some time. But, if he walks at a
speed of 3 m/s, he covers an additional distance of 15 m in the same time. What is the distance he
actually covered?​

Answer 1

Answer:

x15m=distance

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Answer 2

Answer:

The actual covered distance by the man is 22.5 meters

Explanation:

Initial speed of man v= 1 m/s

Initial speed of man v= 1 m/sFinal speed of man v'= 3 m/s

Initial speed of man v= 1 m/sFinal speed of man v'= 3 m/sDistance = 15 m

Now,

Let be the initial distance is d.

We need to calculate the distance

Using formula of speed

v= d/t [v= velocity, d= distance , t = time taken ]

d= vt [By rearranging the above eqn.]........(i)

If he walks at a speed of 3 m/s, he cover an additional distance of 15 m at same time

By using formula of velocity we get::

d+15 = v'*t ........(ii)

Now by dividing (i) and (ii) we get:::

d/(d+15) = vt/v't

=>d/(d+15)=1/3

=>d=7.5

Let d' be the distance covered by the man

Hence

d'=d+15

=>d'=7.5+15

=>d'= 22.5 m