Question

1) A manufacturer sells his product at a loss of 10%. If his selling price was Rs. 14,400, what was his actual loss? what was his cost price?
2) Chalk contains 10% calcium 3% carbon and 12% oxygen. Find the amount of carbon and calcium (in grams) in 2$\frac{1}{2}$ kg
3) Dr. Ritam deposited 25% of her money in the bank after spending 20% of the remainder. She has Rs. 600 left with her. How much did she have originally?
Please help!! I only need the answers no need for an explanation!! It's urgent!

Answer 1

Answer:

1. 1440

Step-by-step explanation:

Loss % = 10%

CP = 14400

As loss is there so CP >SP

Hence, Loss = Cp - Sp

So, we find Sp

Sp = Cp (100-Loss%) / 100

(After solving it)

We get Sp = 12960

Hence loss = Cp-SP

so loss came 1440

Hope it helped

Answer 2

Answer:

(1) Let the C.P of the product be Rs.100

Loss=10%=10% of C.P

= 100

10×100=Rs.10

S.P=C.P−Loss=Rs.100−Rs.10=Rs.90

Thus if S.P is Rs.90 then C.P is Rs.100

If S.P is Rs.14400 then CP= 100/90*14400

= Rs. 16000

Hence Actual C.P=Rs.16,000

Actual loss=C.P−S.P

=16000−14400=Rs.1600

(2) Calcium=10%

Carbon=3%

Oxygen=12%

Remaining=100−(10+3+12)=100−25=75%

Sand=75%

Weight of chalk =2*1/2=5/2kg

Amount of carbon = 5/2*3/100=3/40×1000=75grams

Amount of calcium = 5/2*10/100=1/4Kg= 250grams

and amount of sand= 5/2*75/100=15/8Kg=1.875kg

(3)Let originally she has 100% moneyafter depositing 25% , remains = 75% 20% of 75% again spending so the remaining part of 75% will be 75% will be 80%= 75/80*100= 60. After spending 20 percent of the remainder,she has ₹6000 left with her