Physics, asked by revathisangur2009, 3 days ago

1. A material whose specific resistance is 2 us is drawn into a wire of circular cross- section of radius 0.1mm and length 33 cm. The resistance of the wire is 2. 2112 b. 3.2 12 C. 4.3 Ω d. 12.1

Answers

Answered by Afreenakbar

Answer:

The resistance of the wire is approximately 21.21 Ω(Option A) .

Explanation:

We can apply the following formula to get the wire's resistance:

$R = \frac{(\rho \times L) }{ A}$

where R is the resistance, ρ is the specific resistance, L is the length of the wire, and A is the cross-sectional area of the wire.

Given:

Specific resistance (ρ) = 2 μΩm (2 × 10⁻⁶ Ωm)

Radius (r) = 0.1 mm (0.1 × 10⁻³ m)

Length (L) = 33 cm (33 × 10⁻² m)

We must first determine the wire's cross-sectional area (A):

A = π × r²

A = 3.14159 × (0.1 × 10⁻³)²

A = 3.14159 × 10⁻⁸ m²

Now, using the following formula, we can determine the resistance (R):

$R = \frac{(\rho \times L) }{ A}$

$R = \frac{ (2 \times 10^{-6} \times 33 \times 10^{-2} m) }{ (3.14159 \times 10^{-8} m^2)}$

Calculations being done:

$R = \frac{ (2 \times 33 \times 10^{-8}) }{ 3.14159}$

$R = \frac{ 66 \times 10^{-8} }{ 3.14159}$

R ≈ 21.12 Ω

Therefore, the resistance of the wire is approximately 21.21 Ω(Option A) .