Question

1. A merchant has 120 ltrs of and 180 ltrs of two kinds of oil. He wants the sell oil by
filling the two kinds of oil in tins of equal volumes. What is the greatest of such a tin.​

Answer 1

let a=180 & b=120

By division algorithm,

a=bq+r

180=120*1+60

120=60*2+0

Hence,the greatest volume of tins is 60 ltrs