Question

1) A metal block has dimensions 10 cm x 5 cm x 2 cm and the density of the metal is 8 x 103 kg/m². It is
kept on a table with the face 10 cm x 5 cm in contact with the table. Find the force and pressure exerted
by the block on the table. (g =9.8 m/s2)​

Answer 1

Answer:

Data : 1 = 10 cm, b = 5 cm, h = 2 cm, p= 8 × 10 kg/m3, g = 9.8 m/s2 , A = lb = 10cm × 5cm = 50cm2 = 50 × 104m2 = 5 × 10-5 m2 , force =?, pressure = ? Volume of the block = lbh = 10 cm × 5 cm × 2 cm = 100 cm3 = 100 × 10-6 m3 = 1 × 10-4 m3 Mass of the block = volume × density (∵ density = mass/volume) ∴Mass of the block, m = 1 × 10-4 m3 × 8 × 103 kg/m3 = 0.8 kg Weight of the block = mg = 0.8 kg × 9.8 m/s2 = 7.84 N ∴ The force exerted by the block on the table = 7.84 N. force 7.84 N Pressure = f o r c e a r e a forcearea = 7.84 N 5 × 10 − 3 m 2 7.84N5×10−3m2 = 1.568 × 103 N/m2 or 1.568 × 103 Pa The pressure exerted by the block on the table = 1.568 × 10 N/m2 or 1.568 × 103 Pa.Read more on Sarthaks.com - https://www.sarthaks.com/1730804/a-metal-block-has-thmensions-10-cm-5-cm-2-cm-and-the-density-of-the-metal-is-8-10-3-kg-m-3