Question

1.A metal X forms two oxides A and B. 3 g of A and B contain 0.720 and 1.160 g of oxygen respectively. Calculate the masses of metal in gram which combine with one gram of oxygen in each cases.

Answer 1

Answer:

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Answer 2

GIVEN ;

Mass of oxides A and B = 3g

             A has 0.720g of oxygen

             B has 1.160g of oxygen

TO FIND ;

 The Masses of Metal in gram Which Combine With One gram of Oxygen in Each Cases .

STEP BY STEP EXPLANATION ;

• Here 3 g of oxide A contain 0.720 g of oxygen . Metal present in oxide is =(3-0.720)g =2.28g
• So, 0.72g oxygen combine with =2.28 g of metal

                 1 g oxygen combine with = ( $\displaystyle\frac{2.28}{0.72}$ ) * 1g = 3.16 g

     2.

• Here 3 g of oxide B contain 1.160 g of oxygen . Metal present in oxide is =(3-1.160)g =1.84g
• So, 1.160g oxygen combine with =1.84 g of metal

                 1 g oxygen combine with =( $\displaystyle\frac{1.84}{1.16}$  ) *1g= 1.58 g

So,  The masses of metal which combine with one gram of oxygen in A & B are 3.16 g & 1.58 g respectively