1. A military tent of height 8.25 m is the form of a right circular cylinder of base diameter 30m and height 5.5m surmounted by a right circular cone of same base radius . Find the lenght of the canvas use in making the tent , if the breadth of the cancas is 1.5m .
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Answered by
452
Height of the cone = 8.25 - 5.5= 2.75 m
Slant height of the cone(l)= Under root h^2 + r^2 = 15.25
surface area of cone= pie x r x l = 3.14 x 15 x 15.25= 718.3
surface area of cylinder = 2 x pie x r x h = 2 x 3.14 x 15 x 5.5= 518.1
area of canvas used = 718.3 + 518.1 =1236.4
length of canvas = 1236.4/1.5= 824.3 m
Slant height of the cone(l)= Under root h^2 + r^2 = 15.25
surface area of cone= pie x r x l = 3.14 x 15 x 15.25= 718.3
surface area of cylinder = 2 x pie x r x h = 2 x 3.14 x 15 x 5.5= 518.1
area of canvas used = 718.3 + 518.1 =1236.4
length of canvas = 1236.4/1.5= 824.3 m
Answered by
45
Answer:
Step-by-step explanation:
Height of the cone = 8.25 - 5.5= 2.75 m
Slant height of the cone(l)= Under root h^2 + r^2 = 15.25
surface area of cone= pie x r x l = 3.14 x 15 x 15.25= 718.3
surface area of cylinder = 2 x pie x r x h = 2 x 3.14 x 15 x 5.5= 518.1
area of canvas used = 718.3 + 518.1 =1236.4
length of canvas = 1236.4/1.5= 824.3 m
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