Question

1.
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A monkey starts from the origin and walks
2m east towards a tree and climbs upto a
height 3m and again comes down the tree
walks 4m towards north. Displacement
and distance of the monkey are
​

Answer 1

Distance = 2+3+3+4 = 12 m

Displacement = √(2*2+4*4)

= √20

= 4.472 m

Answer 2

Answer:

Distance = 12m

Displacement = 4.47m

Explanation:

[Refer to the attached image]

Using Pythagoras theorem we get:

The displacement of the monkey from the starting position (s) =  $\sqrt{4^{2} + 2^{2} }$

s = $\sqrt{16 + 4}$

s = 4.47 m

As the monkey climb the tree of 3m so he traveled 3m for climbing up and 3m for climbing down.

And the distance traveled by the monkey = 2m + 3m + 3m + 4m = 12m