Math, asked by Suhanacool6888, 5 hours ago

1) A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

Answers

Answered by JackelineCasarez
0

Answer:

sdasdas

Step-by-step explanation:

Let the son's present age be x

His mother's present age will be 2x

20 years ago,

The age of the mother had been = 2x - 20

The age of the son = x - 20

A.T.Q.

2x - 20 = 10(x- 20)

⇒ (2x - 20) = (10x - 200)

⇒ 8x = 180

⇒ x = 180/8

⇒ x = 22.5

Thus, the mother's present age = 2x

= 22.5 * 2

= 45 years

Learn more: Find the age

brainly.in/question/21219569

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