1) A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?
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Answer:
sdasdas
Step-by-step explanation:
Let the son's present age be x
His mother's present age will be 2x
20 years ago,
The age of the mother had been = 2x - 20
The age of the son = x - 20
A.T.Q.
2x - 20 = 10(x- 20)
⇒ (2x - 20) = (10x - 200)
⇒ 8x = 180
⇒ x = 180/8
⇒ x = 22.5
Thus, the mother's present age = 2x
= 22.5 * 2
= 45 years
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