1) A motor car of mass 1200kg is moving along a straight line with a uniform velocity of
90km/hr. Its velocity is slowed down to 18km/hr in 4s by an unbalanced external force.
Calculate the acceleration and change in momentum. Also calculate the force required.
Answers
Answered by
3
U first need to convert km/hr into m/s by multiply it with 5/18
therefore....v=25m/s
.... u = 5m/s
1).... v = u + at
25 = 5 + a(4)
20 = 4a
a = 5 m/s square
2)...... Change in momentum...
P = m(v-u)
= 1200(25-5)
=1200(20)
= 24000 kgm/s
3) ......F = ma
= 1200*5
= 6000 N.....
Answered by
1
Answer:1).... v = u + at
25 = 5 + a(4)
20 = 4a
a = 5 m/s square
2)...... Change in momentum...
P = m(v-u)
= 1200(25-5)
=1200(20)
= 24000 kgm/s
3) ......F = ma
= 1200*5
= 6000 N.....
Explanation:
Similar questions