Question

1. A motorcycle of mass 2000kg is moving over a horizontal road, with uniform velocity. If this motorcycle has to be stopped with a negative acceleration of -1.5m/s 2, then what is the force of friction between the tyres of motorcycle and the road? the answer is (-3000N) but plz show me the steps

Answer 1

Answer:

- 3000 N

Explanation:

A.T.Q.

Mass, m = 2000 Kg

Acceleration, a = -1.5 m/s^2

Now, According to Newton's Second law of motion,

F = m*a

= 2000*-1.5

= - 3000 N

Therefore,

the force of friction is equal to -3000 N